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Because JSON_QUERY returns a string, using JSON_QUERY in a Where clause is challenging: The JSON object you might be comparing has to be a character-to-character match to the JSON fragment that JSON_QUERY returns.
The following query, for example, will only work if I’m very careful with the contents of the string on the right side of the equals sign (=).
This query, for example, joins the JSON objects in the Last Update column to its table and, based on the customer’s last name, finds those rows where the name in the row and the name in the JSON object don’t match: If you want to retrieve a JSON object so you can change a value in one of its properties, JSON_MODIFY lets you do that.
You must pass the JSON_MODIFY function the JSON object, a JSON path expression to the property you want to change and the value to be inserted into the property.
Alternatively, it’s possible (and maybe even best) to use the function instead to get the actual server name, or machine name, or instance name.These two queries, for example, return identical results: JSON_QUERY doesn’t actually return a JSON object -- the function is only returning a string.Using JSON_QUERY does, however, prevent the string representation of your JSON object from being escaped (that is, having backslashes inserted in front of each of your double quotes).For example, inserting a stray blank space around either of the colons (:) would cause the comparison to fail: You can pass the output of a JSON_QUERY to the OPENJSON function to have the fragment converted to a virtual table, effectively creating a table from a column in the row.You can then join that virtual table to its row using CROSS APPLY.